243^2x-2=(1/9)^x

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Solution for 243^2x-2=(1/9)^x equation: 



243^2x-2=(1/9)^x

We move all terms to the left:

243^2x-2-((1/9)^x)=0



Domain of the equation: 9)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

243^2x-((+1/9)^x)-2=0

We multiply all the terms by the denominator


243^2x*9)^x)-((-2*9)^x)+1=0

We add all the numbers together, and all the variables

243^2x*9)^x)-((-18)^x)+1=0

Wy multiply elements

2187x^3-18)^x)+1=0

We do not support expression: x^3

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